Zhao Xintong vs Robertson Prediction 27 August 2026

Zhao Xintong’s last ten matches highlight his impressive form: he has claimed seven wins and suffered just two defeats. His scoring has been particularly eye-catching, racking up 40 breaks of 50+ and an outstanding 15 centuries, with a highest break of 140. In comparison, his opponents managed only 20 half-centuries and just five centuries against him over the same stretch - a testament to Zhao’s confidence as an attacking player with excellent control over the pace of the game.

In the previous round, he cruised past Barry Hawkins with a 5-2 victory - another indicator of his consistency at this tournament. These numbers not only underline his high scoring in winning efforts but also reflect a well-rounded attacking game: aggression paired with composure when converting opportunities at the table.

Neil Robertson is also enjoying a solid run, having picked up seven wins in his last ten outings, though he has suffered three defeats in that span. What stands out, however, is that his opponents have consistently threatened at the table Robertson has faced 40 breaks of fifty or more, including nine centuries, over the same period. The Australian himself has compiled eight centuries and posted a top break of 122.

His 5-3 victory over Liam Davies underlines his composure in tight finishes, even after a level start to the match. While Robertson boasts an impressive tally of 34 breaks over fifty, the notably higher activity from his opponents suggests occasional lapses in defense or a need to adopt a reactive approach when facing aggressive opposition.